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Almasha
Nov 10, 2026
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Q1. What is Sound?
Verified

Sound is a mechanical wave that originates from the vibration of particles in a medium such as air, water, or solids. These vibrations create longitudinal waves, where particles oscillate parallel to the direction of wave propagation, causing regions of compression and rarefaction.

Q2. Mention the Sources of Sound?
Verified

That object which is basically the cause of vibration is called Source of Sound. For Example; Our clapping hands, chirping birds, Musical instruments etc. as shown in figure.

Q3. Explain the following terms related to sound waves: (a) Wavelength (b) Amplitude (c) Frequency (d) Time Period
Verified

(a) Wavelength: The distance between consecutive crests or troughs (within compressional region or rarefaction region) is called wavelength of sound wave. It is represented by the Greek letter lambda ($\lambda$). Its SI-unit is meter.

(b) Amplitude: It is the maximum displacement covered by particle disturbed when sound wave travels through medium. Amplitude tells about the energy level carried by sound wave. In other words high amplitude indicates high energy and low amplitude tells about low energy of sound wave.

Sound-wave diagram showing direction, rarefaction, compression, amplitude, wavelength, crest, and trough.
Sound-wave diagram showing direction, rarefaction, compression, amplitude, wavelength, crest, and trough.

(c) Frequency: Number of sound waves produced in one second is called frequency. It is symbolically represented by ‘f’. Its SI-unit is hertz (Hz). One hertz means one sound wave is produced in one second.

(d) Time Period: Time required to create one sound wave is called time period. It is symbolically represented by ‘T’. Its SI-unit is second (s).

POINT TO PONDER

A stethoscope works by transmitting sound from the chest-piece to the listener’s ears through air-filled hollow tubes. The chest-piece typically has a plastic disc known as the diaphragm. The diaphragm picks up vibrations from physiological noises.

These vibrations create acoustic pressure waves, which travel up the tubing to the listener’s ears after multiple reflections. The stethoscope amplifies the sounds, making them louder and more easily audible for the listener.

Q4. What is sound? How is it produced? Explain with examples.
Verified

Sound:

Sound is a form of energy, which produces hearing sensation in human ears. Vibrations that travel through the air or another medium and can be heard when they reach a person’s or animal’s ear. Sound waves are longitudinal waves.

Production of sound:

Production of sound totally depends upon vibration of object. Vibrating source transforms energy, due to vibration and it compels the surrounding medium to vibrate through which sound wave travels. The surrounding medium particles perform to and fro motion. Sound waves are such waves which produce sensation of listening when strike with ear drum.

Examples:

  1. In a guitar, sound is produced due to the vibrations of its strings.
  2. Our voice results from the vibrations of our vocal chords.
  3. Human heart beats and vibrations of other organs like lungs also produce sound waves.
  4. Doctors use stethoscope to hear this sound.

Sound is Produced by Vibrating Body:

Experiment:

In school laboratories, we use a device called tuning fork to produce a particular sound. If we strike the tuning fork against rubber hammer, the tuning fork will begin to vibrate.

We can hear the sound produced by tuning fork by bringing it near our ear. We can also feel the vibration by slightly touching one of the prongs of the vibrating tuning fork with a plastic ball suspended from a thread.

Strike a rubber hammer on a tuning fork
Strike a rubber hammer on a tuning fork
Production of sound waves from a vibrating tuning fork
Production of sound waves from a vibrating tuning fork

Production of sound waves from a vibrating tuning fork

Touch the ball gently with the prong of a vibrating tuning fork. The tuning fork will push the ball because of its vibration. Now if we dip the vibrating tuning fork into a glass of water, we will see a splash due to vibration of tuning fork.

Conclusion:

From this activity we can conclude that sound is produced by vibrating bodies.

INFORMATION

Bats can hear frequencies up to 120,000 Hz. Other animals cannot hear such high-pitched sounds. Mice can hear frequencies up to 100,000 Hz, dogs up to 35,000 Hz, and cats up to 25,000 Hz. Humans hear sounds only upto about 20,000 Hz, but children can usually hear higher-frequency sounds than adults.

Q5. Describe the longitudinal nature of sound waves.
Verified

Nature of Sound Wave:

Sound waves are mechanical longitudinal on nature. These waves are also called pressure wave. When any object (source of sound) vibrates, this vibration causes the vibration of molecules of medium (air, fluid etc.). Ultimately this initiated vibration is converted into a chain of vibrations after transferring its energy into molecules of medium till sound wave travels through medium.

Actually when any object vibrates, its vibration shows existence of kinetic energy. This kinetic energy is transmitted to the medium's molecules. These medium's molecules transfer acquired kinetic energy to next molecules of medium. Due to kinetic energy these molecules start vibrational movement in forward direction. By this way vibrational energy produced by sound source is transferred from one point to another point.

COMPRESSION AND RAREFACTION:

Sound waves are the combination of compressions and rarefactions. Compression is that high pressure portion within sound wave, where molecules of medium acquire low velocity, which is produced due to vibrational kinetic energy of sound source. Here molecules of medium have very short distance between them. Rarefaction is that low pressure portion within sound wave, where molecules of medium acquire high velocity within a sound wave which is produced due to vibrational kinetic energy of sound source. Here molecules of medium have comparatively large distance between them as shown in figure.

Tuning fork producing a sound wave with compression, rarefaction and propagation labels
Tuning fork producing a sound wave with compression, rarefaction and propagation labels
Q6. Describe the different types of Sound Waves?
Verified

TYPES OF SOUND WAVES:

Sound waves have different names which are taken as its types. All types of sound waves are basically referenced dependent. For example; Unpleasant or pleasant effect of sound, Soft or hard sound, Musical sound or sound etc. In general sound waves can be categorized as Rhythmic and non-Rhythmic sound waves as shown in figure.

Human ear has limitation of detection of sound waves. The audible range is in between 20 hertz to 20,000 hertz. If wave has frequency less than 20 hertz, it be not audible to our ear, these waves are called “Infrasonic waves”. These are used to detect map-rock, underground petroleum formation, earthquakes etc. Interesting point is that there are so many animals which usually use infrasonic waves for communication across impressive distances for examples; Whales, Elephants, Giraffes etc. Human ear can listen sound having frequencies greater than 20 hertz and less than 20,000 hertz.

Such waves which have frequency greater than 20,000 hertz is called “Ultrasonic waves”. These waves are mostly used in medical field for examination of internal organs of patients. Ultrasonic waves are also used to navigation purposes and so on.

Types of Sound
Types of Sound
Frequency of Sound
Frequency of Sound
Q7. Define the following terms Related to Sounds Waves.
Verified
  1. Wavelength: The distance between two consecutive crests or troughs within compression region or rarefaction region is called wavelength. It is represented by the Greek letter lambda ‘λ’. Its SI unit is meter.
  2. Amplitude: It is the maximum displacement covered by particle disturbed when sound wave travels through medium. Amplitude tells about the energy level carried by sound wave. In other words high amplitude indicates high energy and low amplitude tells about low energy of sound wave.
  3. Frequency: Number of sound waves produced in one second is called frequency. It is symbolically represented by ‘f’. Its SI unit is hertz. One hertz means one sound wave is produced in one second.
  4. Time Period: Time taken by a wave to complete one cycle is called time period. It is symbolically represented by ‘T’. Its SI unit is second.
Properties of Sound Wave
Properties of Sound Wave
Q8. State the approximate range of frequencies audible to humans as 20 Hz to 20000 Hz.
Verified

The average hearing range for a human is between 20 Hz to 20 kHz and uses three muscles to aid the hearing process.

  • The SI unit of frequency is the hertz (Hz).
  • The upper limit in average adults is often closer to 15 - 17 kHz.
  • Below 20 Hz the frequency is called infrasonic frequency.
  • Above 20000 Hz the frequency is called ultrasonic frequency.
Q9. Justify why sound waves cannot travel in a vacuum.
Verified

Because sound is a mechanical wave, it requires some material medium to propagate. The term “vacuum” refers to an empty space that is free of matter particles. As there are no particles in vacuum to cause vibrations, sound cannot travel through vacuum.

Q10. With the help of an experiment, show that sound waves require medium to travel? OR Sound requires material medium for its propagation justify your answer.
Verified

Sound Requires Material Medium for its Propagation:

Sound waves are mechanical longitudinal in nature, so for propagation of sound waves from one point to another, medium is required. Without the existence of medium these waves may be produced by vibrating objects but cannot travel from one place to another. For example, in class room, if air does not exist the students will not be able to listen all lecture points delivered by teacher.

Experiment:

Let’s take an electric bell and an airtight glass bell jar. The electric bell is suspended inside the airtight bell jar. The bell jar is connected to a vacuum pump, as shown in figure.

If you press the switch you will be able to hear the bell. Now switch on the vacuum pump. When the air in the jar is pumped out gradually, the sound becomes fainter, although the same current is passing through the bell. After some time when less air is left inside the bell jar you will hear a very feeble sound. When complete air is pumped out, you will not be able to listen any sound of electric bell. By this experiment, it is clear that medium is necessary for propagation of sound wave.

Conclusion:

From this experiment / activity we conclude that sound waves can only travel / propagate in the presence of air (medium).

Electric bell inside a bell jar connected to an electric connection, switch and vacuum pump
Electric bell inside a bell jar connected to an electric connection, switch and vacuum pump

DO YOU KNOW

The speed of sound in air was first accurately measured in 1738 by members of the French Academy. They used two cannons positioned on hills about 29 kilometers apart. By measuring the time interval between seeing the flash of a cannon and hearing its “boom,” they were able to calculate the speed of sound. To minimize errors from wind and observer reaction times, they fired the cannons alternately. From their observations, they deduced that sound travels at approximately 332 meters per second at 0°C.

Q11. Describe how changes in amplitude and frequency affect the loudness and pitch of sound waves.
Verified

Pitch & loudness:

  • Changes in amplitude and frequency affect the loudness and pitch of sound waves.
  • The frequency of a sound wave is related to its pitch.
  • Sounds with a high pitch have a high frequency (or short wavelength).
  • Sounds with a low pitch have a low frequency (or long wavelength).
  • The amplitude of a sound wave is related to its volume.
  • Sounds with a large amplitude have a high volume.
  • Sounds with a small amplitude have a low volume.

Changes in amplitude and frequency directly affect the perception of sound. Amplitude determines loudness; a larger amplitude corresponds to a louder sound, while a smaller amplitude results in a softer sound. Frequency determines pitch; a higher frequency means a higher pitch (or a “shriller” sound), and a lower frequency corresponds to a lower pitch (or a “deeper” sound).

Loudness of sound wave $\propto$ (Amplitude of sound wave)$^2$.

Loudness of sound
Loudness of sound
Frequency of Sound and Average Range of hearing
Frequency of Sound and Average Range of hearing
Q12. Mention the factor which directly affect the loudness of sound.
Verified

There are basically 4 factors which directly affect the loudness of sound.

  1. Vibrational amplitude of source of sound: Vibrational amplitude has direct relation with loudness of sound. It means that greater the vibration amplitude of vibrating object (Source of sound) will cause the production of high loudness.
  2. Surface area of source of sound: Surface area is directly proportional to relation with loudness of sound. It means that greater the surface area of source of sound will produce of high loudness.
  3. Distance from source of sound: Distance of listener form source of sound has inverse relation with loudness of sound wave. It means that short distance listener will feel more impact of loudness as compare to long distance listener.
  4. Sensitivity of the ears of listener: More sensitive ears can feel more effect of loudness. In other words Sensitivity level of ears has direct relation with loudness of sound wave.
Q13. Differentiate between Pitch and Loudness.
Verified

Difference between Pitch and Loudness:

PitchLoudness
Pitch is the characteristic of sound which is used for differentiating between the shrill and flat sound.Loudness is the property of sound which is used for Differentiating between the loud and faint sound.
Pitch is independent of the energy received by the ear in unit time interval.Loudness is dependent upon the energy received by the ear in unit time interval.
Pitch is dependent on the change in the frequency. As the frequency increases, the shrillness of the sound increases.Loudness is independent of the change in frequency.
Pitch of waves
Pitch of waves
Q14. Describe how different sound sources produce sound waves with different timbres.
Verified

Different sound sources produce sound waves with varying timbres due to differences in their waveforms, which are determined by the combination of frequencies and their relative intensities present in the sound. These differences in waveforms allow us to distinguish between sounds of the same pitch and loudness, such as the sound of a piano versus a guitar.

Detailed explanation:

Waveforms and Overtones:

Sound waves are characterized by their waveforms, which represent how the pressure of the sound wave changes over time. When an object vibrates, it doesn't just produce a single frequency (fundamental frequency), but a combination of frequencies called overtones or harmonics. The relative strengths and frequencies of these overtones significantly affect the waveform.

Instrument-Specific Overtone Profiles:

Different instruments, even when producing the same note (fundamental frequency), generate unique overtone profiles. For example, a violin and a piano playing the same note will produce different sets of overtones, resulting in different waveforms and therefore different timbres.

Perception of Timbre:

Humans perceive these differences in waveforms as differences in timbre, allowing us to differentiate between various instruments, voices, and other sound sources. Timbre can be described using subjective terms like “warm”, “bright”, “dull”, etc., reflecting how our brains process these complex sound wave patterns.

Examples:

  • String instruments: The way a string is plucked or bowed affects the initial vibration and, consequently, the resulting overtone profile and timbre.
  • Wind instruments: The shape and material of the instrument, as well as the way air is blown into it, all contribute to the specific overtone profile.
  • Vocal cords: The shape of the vocal tract and the way vocal cords vibrate create distinct vocal timbres.

Importance of Timbre:

Timbre is crucial for sound identification and musical expression. It allows us to distinguish between different instruments, recognize familiar voices, and appreciate the nuances of musical performance.

Q15. Elaborate the quality of sound or Timber.
Verified

Quality of Sound or Timber:

Quality or timber is that characteristic of sound which helps our ear to distinguish between such two sound waves, which have same loudness and pitch. Timbre is that term which helps us to study dynamic characteristics as well as harmonic contact of sound waves.

Pitch of waves

The word harmonic contact describes that during traveling of sound waves from one point to another point, the way adopted by molecules of medium for transmitting vibrational energy. The quality of sound depends upon relative intensities of overtones. The word over tones means an overtone is any harmonic with frequency greater than the fundamental frequency of a sound.

Characteristics of sound: loudness, pitch and quality or timbre, with examples of waveforms.
Characteristics of sound: loudness, pitch and quality or timbre, with examples of waveforms.
Q16. Describe an echo as the reflection of sound waves.
Verified

An echo is essentially the reflection of sound waves. When sound waves encounter a hard surface, they bounce back, and if the reflected sound reaches the listener’s ear with enough time delay, it is perceived as a distinct echo. The time delay is crucial for distinguishing an echo from the original sound.

Explanations:

Echo Formation:

When the reflected sound waves reach the listener after a sufficient time delay (typically at least 0.1 seconds), it creates the perception of an echo. This delay is necessary for the brain to differentiate the reflected sound from the original sound.

Distance:

The distance between the sound source and the reflecting surface is a key

factor in whether an echo will be heard. For a distinct echo, the reflecting surface needs to be at least 17.2 meters away (assuming a speed of sound of 344 ms−1 and a temperature of 22°C).

Examples:

Caves, canyons, & large empty rooms are good examples of environments where echoes are easily heard because of the large distances and hard surfaces involved.

Q17. Mention the Necessary condition for human hearing of echo sound.
Verified

NECESSARY CONDITION FOR HUMAN HEARING OF ECHO:

Human ear can perceive sound waves within 0.1 second. This value shows that two sound waves can be perceived if time interval between both sound waves is 0.1 second. So it is clear that the time interval gap between Echo and original sound wave is 0.1 second. Due to above mentioned information the distance between source of sound and reflecting surface can be calculated as:

  • Distance travelled by sound ‘D’ = $2d$
  • Time taken by echo ‘t’ = 0.1 s

If the speed of sound is V, then: $v = \frac{D}{t}$ or $D = v \times t$

Putting values: $2d = v \times 0.1$ or $d = v \times \frac{0.1}{2}$

Therefore, $d = \frac{v}{20}$

This result tells that minimum required distance for production of echo is 1/20th value of speed of sound. For example, if speed of sound in air is 340 ms−1 then for producing echo the least distance should be 17 m.

Q18. Justify simple experiments to show the reflection of sound waves.
Verified

Simple experiments demonstrating sound reflection can be done with readily available materials. A basic setup involves using two cardboard tubes and a reflective surface like a wall or a piece of cardboard. By positioning the tubes and the reflector at angles, you can observe how sound waves, emitted from one tube, are redirected towards the other after hitting the surface, proving sound reflection. Another method involves using a ticking clock and a reflecting surface to observe how the sound is redirected to a listener’s ear.

Experiments:

  1. Tube Experiment:

    • Sound Source: A sound source, like a ticking clock or a speaker, is placed at the end of one tube.
    • Reflection: The sound waves travel down the tube and then hit the reflective surface.
    • Re-direction: The reflective surface redirects the sound waves.
    • Observation: When the second tube is positioned to receive the reflected sound, the sound can be heard. This demonstrates that sound waves can be reflected off surfaces.
    • Varying Angles: Changing the angle of the reflective surface allows observation of how the angle of incidence equals the angle of reflection.
  2. Ticking Clock Experiment:

    • Sound Source: A ticking clock is placed at one end of the setup.
    • Reflection: A reflecting surface, like a piece of cardboard or a wall, is positioned to bounce the sound waves.
    • Direction: By adjusting the angle of the reflector, the sound from the clock can be directed towards the listener’s ear.
    • Observation: This shows that sound waves can be redirected by a surface.
Q19. Illustrate a method involving a measurement of distance and time for determining the speed of sound in air.
Verified

A method to measure the speed of sound involves timing how long it takes for a sound to travel a known distance. Two people are positioned a measured distance apart, one with a sound-producing device (like a starting pistol or clappers) and the other with a stopwatch. The second person starts the stopwatch upon seeing the visual cue (flash or clap) and stops it upon hearing the sound. The distance is divided by the time to calculate the speed of sound.

Detailed Steps:

  1. Establish a Distance:

    Measure a suitable distance (e.g., 100 meters or more) between two points in an open area. A trundle wheel or measuring tape can be used for accurate measurement.

  2. Position Participants:

    One person stands at the starting point with a sound-producing device, like a starting pistol or two wooden blocks to clap together. Another person stands at the other end with a stopwatch.

  3. Start the Stopwatch: The person with the stopwatch starts it as soon as they see the visual cue (flash of the pistol or the initial clap).
  4. Stop the Stopwatch: They stop the stopwatch when they hear the sound (the gunshot or the clap echo).
  5. Record Time: Note the time interval recorded on the stopwatch.
  6. Repeat and Average: Repeat the process several times and calculate the average time.
  7. Calculate Speed: Apply the formula: speed = distance / time. The distance is the measured separation between the two people, and the time is the average time taken for the sound to travel that distance.
  8. Considerations: Ensure the environment is relatively quiet and free from obstructions that might distort the sound or create echoes.
Q20. State that the speed of sound in air is approximately 330 - 350 m/s.
Verified

To measure how fast sound travels in air, you can use a stopwatch, a distance measuring tool (like a tape measure or trundle wheel), and a sound source like two blocks of wood that are banged together or a starting pistol. By measuring the time it takes for the sound to travel a known distance, you can calculate the speed of sound.

Method:

  1. Set up the experiment:
    • Choose a distance, preferably over 100 meters, where you can clearly see and hear your partner.
    • Use a tape measure or trundle wheel to accurately measure the distance between two points.
  2. Create a sound and measure the time:
    • One person (Person A) has the sound source (e.g., two blocks of wood, a starting pistol).
    • The other person (Person B) has a stopwatch.
    • Person B starts the stopwatch when they see the sound being made (e.g., the flash of a pistol or the blocks being struck).
    • Person B stops the stopwatch when they hear the sound.
  3. Calculate the speed:
    • Repeat the process multiple times to get an average time.
    • Use the formula: speed = distance / time.
    • For example, if the distance is 100 meters and the average time is 0.3 seconds, the speed of sound would be approximately 333 ms−1.

    If the speed of sound is V, then: speed = distance / time or $v = \frac{d}{t}$.

Q21. How temperature affect speed of sound.
Verified

Temperature directly affects the speed of sound; higher temperatures lead to faster sound propagation, while lower temperatures result in slower sound speeds. This is because warmer temperatures cause molecules to vibrate faster, enabling sound waves to travel more quickly through the medium. This is because higher temperatures provide more energy to the particles in the medium, causing them to vibrate more rapidly and transfer sound waves more efficiently. For instance, the speed of sound in air at 0°C is approximately 331 metres per second, but it increases to about 343 metres per second at 20°C.

Q22. You often see lightning before hearing thunder. Why?
Verified

You see lightning before you hear thunder because light travels much faster than sound. The flash of lightning and the sound of thunder occur simultaneously, but because light’s speed is significantly greater, the light reaches your eyes almost instantly, while the sound takes considerably longer to travel to your ears. Light and sound don’t travel at the same speed. The speed of light is about 300,000 kilometres per second. So the light – in the form of a flash of lightning – reaches you very quickly. Much faster than the sound (the thunder). Because the speed of sound is about 330 metres per second.

Q23. Describe that, in general, sound travels faster in solids than in liquids and faster in liquids than in gases.
Verified

Sound waves generally travel faster in solids than in liquids and faster in liquids than in gases. This is primarily due to the density and how closely packed the molecules are in each medium. In solids, molecules are tightly bound, allowing sound waves to propagate quickly. Liquids have molecules that are closer than in gases, but not as tightly packed as in solids, so sound travels slower than in solids but faster than in gases. Gases have the most spread-out molecules, leading to the slowest sound wave transmission.

  • Essentially, the denser the medium (meaning the more closely packed the molecules are), the faster sound waves can travel through it.
  • One can also increase the speed of sound by increasing the temperature of the medium. The higher the temperature, the higher the kinetic energy, hence a faster speed of sound.
Q24. Define ultrasound as sound with a frequency higher than 20 kHz.
Verified

Any sound with a frequency above 20,000 Hz (or 20 kHz) – that is, above the highest audible frequency – is defined to be ultrasound. Ultrasound is sound with a frequency higher than 20 kHz, which is above the upper limit of human hearing. This means that humans cannot hear sounds in the ultrasound range. Ultrasound is used in various applications, including medical imaging and non-destructive testing of materials.

Q25. What are Infrasound?
Verified

Infrasound refers to sound waves with frequencies below the threshold of human hearing, typically below 20 Hz. These low-frequency sound waves are often produced by natural events like earthquakes, volcanoes, and large storms, as well as by human activities like explosions and large machinery. While humans generally can’t hear infrasound, it can be detected by specialized instruments like microbarometers and can have subtle effects on humans and animals.

Q26. How Infrasound can be generated by natural events.
Verified

Infrasound is generated by natural events like earthquakes, volcanic eruptions, and explosions. Specialized instruments called infrasound sensors detect these low-frequency sound waves. Monitoring seismic activity to predict earthquakes and volcanic eruptions. Studying and understanding the behavior of natural disasters. It provides early warnings for natural disasters. It also helps in understanding the Earth’s internal processes. For example, infrasound sensors placed around a volcano can detect low-frequency rumblings that indicate an imminent eruption, allowing timely evacuation of nearby populations.

Q27. Infrasound can travel incredibly long distances without losing much of its energy. Comments
Verified

Infrasound can travel incredibly long distances without losing much of its energy. This means that infrasound waves produced by natural events, such as volcanic eruptions or earthquakes, can be detected thousands of kilometers away from their source. For instance, the infrasound waves generated by the eruption of Krakatoa in 1883 were recorded all around the world, circling the globe multiple times. This long-range propagation makes infrasound a powerful tool for monitoring and studying geological and atmospheric phenomena on a global scale.

Q28. Explore the characteristics of sound waves including pitch and loudness.
Verified

Sound waves can be characterized by their pitch and loudness, which are directly related to the wave’s frequency and amplitude, respectively. High-frequency sound waves are perceived as having a high pitch, while low-frequency waves are perceived as having a low pitch. Loudness is determined by the amplitude of the wave; larger amplitudes correspond to louder sounds. Pitch describes about number of vibrations produced by vocal chord in unit interval of time (one second). That’s why pitch has direct relation with frequency of sound wave.

Pitch of sound wave $propto$ Frequency of sound wave

For example: A bird produces high-pitched sound whereas roaring of a lion is a low-pitched sound, the voice of a woman has a higher pitch than that of a man and soon.

Pitch of Sound; diagram showing low and high pitch and low and high frequency waveforms
Pitch of Sound; diagram showing low and high pitch and low and high frequency waveforms
Q29. Illustrate and analyze the uses of Ultrasound [in cleaning, prenatal and other medical scanning, and in sonar.
Verified

Uses of Ultrasound in cleaning:

High-frequency sound waves create tiny bubbles in a liquid. These bubbles implode, producing small shock waves that clean surfaces.

  • Applications: Cleaning jewelry, electronic parts, and surgical tools.
  • Advantages: Non-damaging, reaches small and hard-to-clean areas, often only needs water or mild detergents.

Uses of Ultrasound in prenatal:

Prenatal ultrasound is a widely used, non-invasive imaging technique that utilizes sound waves to visualize a fetus within the womb, providing valuable information about the pregnancy and fetal development.

Uses of Ultrasound in medical scanning:

A device called a transducer sends high-frequency sound waves into the body. The sound waves bounce off tissues and return to the transducer, creating an image.

  • Applications: Monitoring fetal development during pregnancy. Checking heart function (echocardiograms) and blood flow (Doppler ultrasound).
  • Advantages: Non-invasive, safe (no harmful radiation), provides real-time images.

Uses of Ultrasound in sonar (sound navigation and ranging):

A sonar device sends out sound pulses underwater. The pulses hit objects and return as echoes. The time it takes for the echoes to return is used to calculate distance.

  • Applications: Mapping the ocean floor, finding underwater objects like shipwrecks, and measuring water depth.
Q30. Illustrate the use of infrasound.
Verified

Infrasound, sound waves with frequencies below the range of human hearing (typically below 20 Hz), is used in various applications, including monitoring natural events, studying the Earth’s interior, and even animal communication. It's also employed in industrial settings for cleaning and in some medical contexts. Infrasound can be used to investigate the internal structure of our planet, just like ultrasound is used for foetal scanning. Earthquakes produce very powerful seismic waves that can be classed as infrasound waves.

Q31. Analyze the effects of noise pollution on the environment.
Verified

Noise pollution negatively impacts the environment by disrupting animal communication, causing stress, and altering ecosystems. It affects wildlife on land and in the sea, interfering with predator-prey relationships. Furthermore, noise pollution can contribute to habitat degradation & species displacement, unbalancing the natural environment. The displacement of animals due to noise pollution can disrupt entire ecosystems by altering predator-prey relationships and impacting the distribution of plant and animal species.

Q32. Explore the concept of noise including periodic sound waves and non periodic sound waves.
Verified

The term noise means unpleasant sound waves experienced by listener. But in physics noise has following characteristics; these sound waves have:

  • Non-Rhythmic behavior
  • Irregular time intervals for completion of vibrations
  • Variable energy states
  • Irregular intensities

‘Periodic sound waves’ and ‘non-periodic sound waves’. Human ears structures are designed for periodic sound waves. It means that our ears feel pleasant effect for those sound waves which have regular periodic vibrations, energies, frequencies and even intensities levels. The range of periodic sound waves is about 15 hertz to 4000 hertz. While beyond this range periodic sound waves are converted into non-periodic waves, which give very unpleased effect to listener. Beyond this range receiving sound signals are painful.

Q33. Mention the impact of noise on human health.
Verified

Noise is also one of the main causes for creating psychological and physical stress in daily routine. Noise also provides negative impact on concentration level to perform any a daily life activity. We all are mostly affected by environmental noise sources for examples:

  • Industrial buildings: factories and machineries, air-conditioning systems.
  • Construction sites: site formation (e.g. excavation), piling, roadwork, demolition, renovation.
  • Transportation: aircrafts, trains, road vehicles, vessels.
  • Public places: open markets, streets, parks.

Noise pollution can be reduced by use of earplugs, turning off appliances when not in use, planting more trees, lowering the volume, regular maintenance of vehicles and machines etc. By controlling noise we can control negative health effects that noise pollution has on everyone.

Q34. If you heard the sound of thunder, you are safe now, how?
Verified

It is because thunder has occurred a bit earlier and you heard the sound later because sound travels at much lower speed than light. But still it is instructed to find some covered space and stays there during thunder.

Q35. Mention the Importance of Acoustic Protection.
Verified

Acoustic protection is crucial for various reasons, primarily because excessive noise exposure can negatively impact human health, communication, and productivity. It also plays a role in preserving privacy and maintaining a comfortable environment in both residential and workplace settings.

IMPORTANCE OF ACOUSTIC PROTECTION:

Acoustic protection is crucial for several key reasons:

  1. Health and Well-being:
    • Hearing Protection: Prevents hearing loss from prolonged noise exposure.
    • Mental Health: Reduces stress, anxiety, and sleep disorders by minimizing noise pollution.
  2. Productivity and Performance:
    • Workplace Efficiency: Enhances concentration, reduces errors, and prevents accidents by limiting distractions.
    • Learning Environments: Improves student's ability to focus and retain information.
  3. Environmental and Community Impact:
    • Wildlife Preservation: Protects animals that rely on sound for communication and navigation.
    • Quality of Life: Ensures quieter, more pleasant living environments for communities.
  4. Legal and Regulatory Compliance:
    • Occupational Safety: Helps organizations meet noise exposure regulations.
    • Building Standards: Ensures buildings provide adequate noise control as per codes.
  5. Technological and Industrial Development:
    • Innovation: Drives the creation of new materials and quieter machinery, benefiting various industries.
Q36. What is the typical material used to make drumheads?
Verified

Animal skins like calf skin or goat skin are used to make drum heads. Although some modern drumheads are often made of plastic or synthetic materials, but traditional drumheads were made from animal skin.

Q37. What is the main benefit of acoustic protection?
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Without acoustic protection, people can suffer hearing loss and increased stress levels. Productivity in workplaces and learning environments may drop due to constant noise distractions. Additionally, excessive noise can disrupt community peace and harm wildlife. By absorbing echoes, reducing background sounds and limiting other noises, acoustic protection can make it easier for people to hear one another in any environment. Avoiding accidents is much more manageable when people can focus and communicate efficiently.

Q38. Describe how knowledge of the properties of sound waves is applied in the design of buildings with respect to acoustics.
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APPLYING ACOUSTICS IN BUILDING DESIGN:

Understanding sound wave properties is crucial for designing buildings with good acoustics

  1. Sound Absorption: Materials like carpets, acoustic panels, and curtains are used to absorb sound and reduce echoes.
  2. Sound Reflection: Design of walls and ceiling are made in such a way that it reflects sound where needed, materials like glass and concrete are used for such purpose.
  3. Sound Transmission: We Use thick walls, double-glazed windows, and insulated doors to prevent sound from traveling between spaces. Mostly Dense Materials or Heavy materials like concrete block are used.
  4. Sound Diffusion: For acoustic protection we install elements that scatter sound evenly, like irregular surfaces or special panels.
  5. Resonance Control: The size and design of the room are taken in consideration to avoid amplification of certain sounds. Also Bass Traps are used in these studios to control low-frequency sounds.
  6. Noise Control: Gaps are properly sealed to ensure that doors and windows are well-sealed to block noise. Also barrier walls, fences, and landscaping are used to reduce outside noise.
  7. Vibration Control: For damping we use rubber mounts and floating floors to reduce vibrations. And isolate noisy equipment to prevent vibrations from spreading.

Practical examples are Concert halls in which combine absorbing, reflecting, and diffusing materials for clear sound. In offices we use absorbing materials to reduce noise and increase productivity. In homes incorporate soundproofing are used for privacy and quiet. Using sound wave properties helps design buildings that sound good and are comfortable. Soft materials are used on walls of classrooms and public buildings in order to reduce echo, which have following benefits.

  • Sound Absorption: Soft materials like carpets, curtains, and acoustic panels absorb sound waves, reducing reflections and echoes. It ensures students can hear and understand the teacher effectively, leading to better learning outcomes.
  • Reducing Reverberation Time: Soft materials shorten the time it takes for sound to decay, making speech and other sounds clearer. It creates an environment conducive to concentration and productivity in spaces like libraries and lecture halls. A quieter environment reduces stress and fatigue, enhancing comfort in places like hospitals and auditoriums.
Q39. Explain the use of soft materials to reduce echo sounding.
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When a sound wave hits a hard surface, like wood or metal, it bounces back and creates an echo. However, soft materials can absorb sound and stop an echo cold. Lining spaces with soft surfaces helps reduce echoes, which is why sound booths are completely lined with acoustic foam and other soft materials. Simple adjustments like adding rugs, cushions, and window curtains can absorb sound, while more advanced solutions, such as acoustic wall panels, provide effective soundproofing. These echo-reducing panels absorb and diffuse sound waves, significantly reducing overall echo.

Q40. Mention the main Applications of Echo?
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APPLICATIONS OF ECHO:

There are so many applications of echo are common in daily life; by the help of echo.

  • Speed of sound can be determined.
  • Usage in obstetric ultra sonography and so on.
  • Bats cannot see from their eyes by the help of echolocation they can reach their destinations and can identify things which come on their ways.
  • Depth of sea or presence of submarines can be located by echo-techniques.
Q41. What is Reverberation?
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Reverberation:

Reverberation is the phenomenon of overlapping of sound caused by multiple reflections. It causes the overlapping of several reflected waves. If the time gap between the reflected waves is so short that these cannot be distinguished. So we hear multiple noisy sounds.

Q42. Explain, with examples, how sound can reflect, refract and diffract.
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Sound waves exhibit reflection, refraction, and diffraction, just like other waves. Reflection occurs when sound waves bounce off a surface, like an echo. Refraction happens when sound waves change direction as they pass from one medium to another, such as when sound bends towards the cooler ground at night due to temperature differences. Diffraction is the bending of sound waves around obstacles or through openings, which allows you to hear someone speaking even when they are around a corner.

(i) Reflection:

  • Definition: Reflection is the bouncing back of sound waves when they encounter a surface. The angle of incidence (the angle at which the wave hits the surface) is equal to the angle of reflection (the angle at which it bounces off).
  • Example: The most common example is an echo. When you shout in a large room with hard surfaces, the sound waves bounce off the walls, creating a delayed repetition of your voice.
  • Another Example: Sonar uses the reflection of sound waves to map the ocean floor or detect objects underwater.

(ii) Refraction:

  • Definition: Refraction is the bending of sound waves as they pass from one medium to another or when the medium has varying properties (like temperature).
  • Example: Sound waves refract when traveling through air layers at different temperatures. Cooler air is denser; causing sound waves to bend towards it. This is why sound can travel further at night, when the air near the ground is cooler.
  • Another Example: Sound waves can also refract when passing through materials of different densities, such as air and water.

(iii) Diffraction:

  • Definition: Diffraction is the spreading out of sound waves as they pass through an opening or around an obstacle.
  • Example: You can hear someone speaking even when they are around a corner or behind a tree. This is because the sound waves diffract, or bend, around the obstacle.
  • Another Example: The ability of sound to diffract also explains why you can hear sounds from a loudspeaker even when you are not directly in front of it. The sound waves spread out as they leave the speaker, filling the room.
Q43. Explain how sound is converted by the eardrum and nerves into electrical signals that are then interpreted by the brain.
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Sound waves are converted into electrical signals in the ear, primarily within the cochlea, and then transmitted to the brain via the auditory nerve for interpretation. The eardrum and ossicles in the middle ear amplify and transmit these vibrations. In the cochlea, hair cells convert these vibrations into electrical signals, which are then carried to the brain by the auditory nerve.

  1. Sound waves enter the ear: Sound waves, which are essentially vibrations in the air, travel down the ear canal and strike the eardrum (tympanic membrane).
  2. Eardrum and ossicle vibration: The eardrum vibrates in response to the sound waves. These vibrations are then amplified and transmitted through the three tiny bones of the middle

ear (malleus, incus, and stapes, also known as the hammer, anvil, and stirrup).

  1. Inner ear and cochlea: The vibrations of the stapes bone are transferred to the oval window, which is the entrance to the inner ear. This movement causes fluid within the cochlea (a snail-shaped structure in the inner ear) to ripple.
  2. Hair cell transduction: Inside the cochlea are thousands of tiny hair cells, each with hair-like structures called stereocilia. These hair cells are embedded in the fluid. As the fluid ripples, it causes the stereocilia to bend. This bending opens ion channels, causing a rush of ions into the hair cells and creating an electrical signal.
  3. Auditory nerve and brain: The electrical signals generated by the hair cells are transmitted to the auditory nerve (also called the vestibulocochlear nerve or cranial nerve VIII). This nerve carries the signals to the brain, specifically to the auditory cortex in the temporal lobe.
  4. Brain interpretation: The auditory cortex interprets these electrical signals, processing them to recognize the sound's characteristics like pitch, loudness, and location, and ultimately allowing us to perceive the sound.

OR (Second Answer)

The process of converting sound into electrical signals that are interpreted by the brain involves several steps that can be described through the principles of wave mechanics, mechanical vibrations, and signal transduction.

  1. Sound Waves Enter the Ear: Sound waves are vibrations in the air that travel into the ear canal and hit the eardrum.
  2. Eardrum Vibration: The eardrum vibrates in response to these sound waves.
  3. Ossicles Amplify Vibrations: These vibrations are passed to three tiny bones in the middle ear called the ossicles (malleus, incus, and stapes), which amplify the vibrations.
  4. Vibrations Enter the Cochlea: The stapes (one of the ossicles) sends the vibrations into the cochlea, a fluid-filled spiral structure in the inner ear.
  5. Fluid Waves in the Cochlea: The vibrations create waves in the fluid inside the cochlea.
  6. Hair Cells Detect Vibrations: These fluid waves move the basilar membrane inside the cochlea, causing hair cells on the membrane to bend.
  7. Conversion to Electrical Signals: When the hair cells bend, they generate electrical signals.
  8. Electrical Signals Travel to the Brain: These electrical signals are sent through the auditory nerve to the brain.
  9. Brain Interprets the Signals: The brain processes these signals and interprets them as sound, such as music or speech.
Human Hearing System
Human Hearing System
Q44. What is the drawback of continuous use of hand free devices like earphones and headphones.
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Continuous use of hands-free devices like earphones and headphones, especially at high volumes, can lead to noise-induced hearing loss (NIHL), tinnitus (ringing in the ears), ear infections from bacteria on dirty earphones, and temporary hearing fatigue. To protect your hearing, follow the 60/60 rule (no more than 60% volume for 60 minutes), use noise-canceling headphones, take regular breaks, opt for over-ear headphones, and get regular hearing checks. These measures help minimize the risk of hearing damage while using these devices.

Q45. Mention the Sensitivity of human ear for detection of sound.
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The human ear is incredibly sensitive and can detect a wide range of sounds. It can hear sounds as quiet as a whisper (about 20 decibels) to as loud as a rock concert (about 120 decibels). This wide range of sensitivity is due to the precise way the inner ear's hair cells and auditory nerve work together to convert sound waves into electrical signals for the brain to interpret.

Examples:

Example 13.1: A ship sends sound waves in the Pacific Ocean and they take 14.7 s to return to the ship. Find the depth of the Pacific Ocean.
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GIVEN:

  • Speed of sound in water, $v = 1500\ \mathrm{m\,s^{-1}}$
  • Time taken by sound to return, $t = 14.7\ \mathrm{s}$

REQUIRED:

Depth of the Pacific Ocean, $d = ?$

SOLUTION:

For the round trip of the sound, $d = \frac{v \times t}{2}$.

Putting values: $d = \frac{1500\ \mathrm{m\,s^{-1}} \times 14.7\ \mathrm{s}}{2}$.

Therefore, $d = 11{,}025\ \mathrm{m} = 11.025\ \mathrm{km}$.

The depth of the Pacific Ocean is approximately $11{,}025\ \mathrm{m}$.

Example 13.2: A boy at night heard the sound of thunder with a gap of about 3.0 seconds when he saw lightning. How far away is the lightning, taking the speed of sound as 343 ms⁻¹?
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GIVEN:

  • Speed of sound, $v = 343\ \mathrm{m\,s^{-1}}$
  • Time taken, $t = 3.0\ \mathrm{s}$

REQUIRED:

Distance of lightning, $d = ?$

SOLUTION:

Speed of sound is given by $v = \frac{d}{t}$, or $d = v \times t$.

Putting values: $d = 343\ \mathrm{m\,s^{-1}} \times 3.0\ \mathrm{s}$.

Therefore, $d = 1029\ \mathrm{m} = 1.029\ \mathrm{km}$, and the source rounds this to $1\ \mathrm{km}$.

Therefore, the clouds are at about $1\ \mathrm{km}$ distance.

Example 13.3: A teacher took students to a nearby hill for an echo experiment. Abdullah shouted and the teacher and all other students heard his echo after 1.2 s, using a stopwatch. If the speed of sound is 346 ms⁻¹, how far will the cliff be from him?
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GIVEN:

  • Time taken for echo, $\Delta t = 1.2\ \mathrm{s}$
  • Speed of sound in air, $v = 346\ \mathrm{m\,s^{-1}}$

REQUIRED:

Distance of cliff, $d = ?$

SOLUTION:

Using the equation for echo: $d = \frac{v \times \Delta t}{2}$.

Putting values: $d = \frac{(346\ \mathrm{m\,s^{-1}}) \times (1.2\ \mathrm{s})}{2}$.

Therefore, $d = 207.6\ \mathrm{m}$.

So, the cliff is $207.6\ \mathrm{m}$ away from him.

Summary

  • Sound is a disturbance of matter that is transmitted from its source to outwards and which produces sensation of hearing in ear.
  • Speed of Sound in air is approximately $330$–$350\ \mathrm{m\,s^{-1}}$.
  • Loudness is the perception of sound intensity; greater the intensity, louder the sound will be.
  • Pitch is the perception of frequency of sound; greater the frequency, greater will be the pitch and shriller will be the sound.
  • Quality is number and relative intensity of multiple sound frequencies.
  • Musical Sound is a sound that is pleasant and harmonious.
  • Noise is any loud, discordant or disagreeable sound.
  • Acoustic Protection is the application of soft and porous material to protect individuals against undesirable sounds and noises.
  • Audible Frequency Range is the range of frequency from $20\ \mathrm{Hz}$ to $20{,}000\ \mathrm{Hz}$ that humans can hear.
  • Infrasound waves are the sound waves having frequency less than $20\ \mathrm{Hz}$, which human cannot hear.
  • Ultrasound waves are the sound waves having frequency greater than $20\ \mathrm{kHz}$, which human cannot hear.
  • Reverberation is the reflected sound that cannot be distinguished from original sound (is heard before $0.1\ \mathrm{s}$ of the original sound).
  • Echo is the reflected sound that can be distinguished from original sound (is heard after $0.1\ \mathrm{s}$ or more of the original sound).