Practice Quiz Mode
Take all 5 MCQs in interactive quiz mode with timer and progress tracking
$$f(x)=9(4)^{x}$$
The function $f$ is defined by the given equation. If $g(x)=f(x+2)$, which of the following equations defines the function $g$?
Difficulty: Hard
A:
$g(x)=18(4)^{x}$
B:
$g(x)=144(4)^{x}$
C:
$g(x)=18(8)^{x}$
D:
$g(x)=81(16)^{x}$
If a and c are positive numbers, which of the following is equivalent to $\sqrt{(a+c)^{3}}\cdot\sqrt{a+c}$?
Difficulty: Hard
A:
$a+c$
B:
$a^{2}+c^{2}$
C:
$a^{2}+2ac+c^{2}$
D:
$a^{2}c^{2}$
The total revenue from sales of a product can be calculated using the formula $T=PQ$, where $T$ is the total revenue, $P$ is the price of the product, and $Q$ is the quantity of the product sold. Which of the following equations gives the quantity of product sold in terms of $P$ and $T$?
Difficulty: Easy
A:
$Q=\dfrac{P}{T}$
B:
$Q=\dfrac{T}{P}$
C:
$Q=PT$
D:
$Q=T-P$
The function $f$ is defined by $f(x)=x^{3}+15$. What is the value of $f(2)$?
Difficulty: Easy
A:
20
B:
21
C:
23
D:
24
Kao measured the temperature of a cup of hot chocolate placed in a room with a constant temperature of 70 degrees Fahrenheit (${}^{\circ}$F). The temperature of the hot chocolate was 185${}^{\circ}$F at 6:00 p.m. when it started cooling. The temperature of the hot chocolate was 156${}^{\circ}$F at 6:05 p.m. and 135${}^{\circ}$F at 6:10 p.m. The hot chocolate's temperature continued to decrease. Of the following functions, which best models the temperature $T(m)$, in degrees Fahrenheit, of Kao's hot chocolate $m$ minutes after it started cooling?
Difficulty: Hard
A:
$T(m)=185(1.25)^{m}$
B:
$T(m)=185(0.85)^{m}$
C:
$T(m)=(185-70)(0.75)^{\frac{m}{5}}$
D:
$T(m)=70+115(0.75)^{\frac{m}{5}}$
Premium content
Sign in and upgrade to continue reading.