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Vectors and Equilibrium - Set 1
Home
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NUST Entrance Test
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Physics
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Vectors and Equilibrium
Set 1
MM
Mashaal Masha
Oct 11, 2022
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Choose the correct options for the following questions.
Choose the set of physical quantities which have both numerical and directional properties:
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Difficulty: Easy
A:
Velocity, mass
B:
Speed, acceleration
C:
Acceleration, weight
D:
Distance, force
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The direction of a vector in space requires:
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Difficulty: Easy
A:
X-axis
B:
X and Y axis
C:
XYZ axis
D:
Y and Z axis
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$n\overrightarrow{A}$ has same direction as that of $\overrightarrow{A}$ when n is ______
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Difficulty: Easy
A:
positive
B:
negative
C:
zero
D:
A and B
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If n represents a physical quantity in the product $n\overrightarrow{A}$, then dimensions of $n\overrightarrow{A}$ will be:
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Difficulty: Easy
A:
Same as that of $\overrightarrow{A}$
B:
Zero
C:
Product of dimensions of n and $\overrightarrow{A}$
D:
Dimensions of $\overrightarrow{A}$ divided by that of n
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When $\overrightarrow{A}$ is added to its negative, we get:
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Difficulty: Easy
A:
$2\overrightarrow{A}$
B:
Null vector
C:
$\overrightarrow{A}$
D:
$-2\overrightarrow{A}$
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Two vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ are said to be equal if they have:
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Difficulty: Easy
A:
Same magnitudes but different directions
B:
Different magnitudes but same directions
C:
Different magnitudes and directions
D:
Same magnitude and directions
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The direction of a vector in space is specified by:
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Difficulty: Easy
A:
One angle
B:
Two angles
C:
Three angles
D:
None
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Parallel vectors of same magnitudes:
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Difficulty: Easy
A:
Are equal
B:
Are unequal
C:
When added, give the sum equal to zero
D:
When multiplied, give the answer equal to zero
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If a vector $\overrightarrow{A}$ makes an angle $\theta$ with x-axis, then:
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Difficulty: Hard
A:
$A_{x}=A\sin\theta$
B:
$A_{x}=A\cos\theta$
C:
$A=A_{x}\cos\theta$
D:
$A=A_{x}\sin\theta$
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In a triangle OPQ, if $Q=90^{\circ} and OP is hypotenuse, then:
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Difficulty: Hard
A:
$(OP)^{2}=(PQ)^{2}-(OQ)^{2}$
B:
$(OQ)^{2}=(OP)^{2}-(PQ)^{2}$
C:
$(PQ)^{2}=(OP)^{2}+(OQ)^{2}$
D:
$(OQ)^{2}=(PQ)^{2}-(OP)^{2}$
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Set 2
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