E
Editor
Sep 18, 2022
Two identical conducting spheres A and B carry equal charge Q. They are separated by a distance much larger than their diameters. A third identical conducting sphere C carries charge 2Q. Sphere C is first touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes
Difficulty: Easy
A:
$\rm{\frac{F}{2}}$
B:
$\rm{\frac{15F}{8}}$
C:
$\rm{\frac{5F}{7}}$
D:
$\rm{\frac{2F}{5}}$
ID: 63273db7ca83163ac3a0d443