$\sin[\frac{\pi}{2}-\sin^{-1}(\frac{-\sqrt{3}}{2})]$=

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$\sin[\frac{\pi}{2}-\sin^{-1}(\frac{-\sqrt{3}}{2})]$=

E

Editor

Sep 18, 2022

$\sin[\frac{\pi}{2}-\sin^{-1}(\frac{-\sqrt{3}}{2})]$=

Difficulty: Easy

A:

1/2

B:

\frac{-\sqrt{3}}{2}

C:

\frac{1}{\sqrt{2}}

D:

\frac{-1}{\sqrt{2}}

ID: 63273db9ca83163ac3a11487