In the expression $3(2x^{2}+px+8)-16x(\rho+4)$, $\rho$ is a constant. This expression is equivalent to the expression $6x^{2}-155x+24$. What is the value of $\rho$?
MM
Mashaal Masha
Feb 20, 2024
In the expression $3(2x^{2}+px+8)-16x(p+4)$, $p$ is a constant. This expression is equivalent to the expression $6x^{2}-155x+24$. What is the value of $p$?