A machine launches a softball from ground level. The softball reaches a maximum height of 51.84 meters above the ground at 1.8 seconds and hits the ground at 3.6 seconds. Which equation represents the height above ground $h$, in meters, of the softball $t$ seconds after it is launched?

Question

Accepted Answer

$h=-16(t-1.8)^{2}+51.84$

Answer

$h=-t^{2}+3.6$

Answer

$h=-t^{2}+51.84$

Answer

$h=-16(t-1.8)^{2}-3.6$