$^{n}C_{r}+2^{n}C_{r-1}+^{n}C_{r-2}$=

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$^{n}C_{r}+2^{n}C_{r-1}+^{n}C_{r-2}$=

E

Editor

Sep 18, 2022

$^{n}C_{r}+2^{n}C_{r-1}+^{n}C_{r-2}$=

Difficulty: Easy

A:

^{n+1}C_{r}

B:

^{n-1}C_{r}

C:

^{n+2}C_{r}

D:

^{n-2}C_{r-1}

ID: 63273dbaca83163ac3a12491