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Inverse of $A=\begin{bmatrix}a & b \\c & d… | ClassNotes
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Sep 18, 2022
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Inverse of $A=\begin{bmatrix}a & b \\c & d \end{bmatrix}$ is:
Difficulty: Easy
A:
$\frac{1}{adbc}\begin{bmatrix}a & b \\c & d \end{bmatrix}$
B:
$\begin{bmatrix}-ad & bc \\c & d \end{bmatrix}$
C:
$\begin{bmatrix}1 & 0 \\0 & 1 \end{bmatrix}$
D:
None of these
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ID: 63273dbaca83163ac3a11e2f
