If $\sin\theta=\frac{12}{13}$, and $\sin\theta>0$, then $\tan\theta+$

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If $\sin\theta=\frac{12}{13}$, and $\sin\theta>0$, then $\tan\theta+$

E

Editor

Sep 18, 2022

If $\sin\theta=\frac{12}{13}$, and $\sin\theta>0$, then $\tan\theta+$

Difficulty: Easy

A:

\frac{2}{5}

B:

-\frac{12}{13}

C:

\frac{13}{5}

D:

\frac{12}{5}

ID: 63273dbaca83163ac3a131f3