If $\int_{0}^{1}\frac{1}{(2x+K)^{2}} dx=1/3$, where K is a constant, then the value of K is

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If $\int_{0}^{1}\frac{1}{(2x+K)^{2}} dx=1/3$, where K is a constant, then the value of K is

E

Editor

Sep 18, 2022

If $\int_{0}^{1}\frac{1}{(2x+K)^{2}} dx=1/3$, where K is a constant, then the value of K is

Difficulty: Easy

A:

1

B:

-3

C:

4

D:

1 or -3

ID: 63273db9ca83163ac3a10e03