If $f(x)=\sqrt{x+1}$ and $g(x)=\frac{1}{x^{2}}$ then fof(x)=

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If $f(x)=\sqrt{x+1}$ and $g(x)=\frac{1}{x^{2}}$ then fof(x)=

E

Editor

Sep 18, 2022

If $f(x)=\sqrt{x+1}$ and $g(x)=\frac{1}{x^{2}}$ then fof(x)=

Difficulty: Easy

A:

\frac{1}{x+1}

B:

\frac{3(x-1)}{4-x}

C:

\frac{3}{2x}

D:

\frac{1}{{\sqrt{\sqrt{x+1}+1}}}

ID: 63273db8ca83163ac3a106cb