If $f(x)=\frac{1}{\sqrt{x^{2}-1}}$, then f'(x) equals:

Loading...

Command Palette

Search for a command to run...

ClassNotes

Human-reviewed study resources for board exams, entry tests, and structured practice across notes, MCQs, flashcards, and past papers.

Support: [email protected]

Business: [email protected]

North America: +1 (512) 666-1423

Asia / MENA: +92 340 9170227

We typically reply within 3 business days.

Explore

Classes
Posts
MCQs
Flashcards
Search

Company

About
Contact
Tutors
Editorial Standards

Policies

Privacy Policy
Terms of Use
Cookie Policy
Refund Policy
Shipping Policy

© 2026 ClassNotes Inc. All rights reserved.

Allen, Texas and Lahore, Pakistan. Public support pages are available for privacy, terms, cookies, refunds, shipping, and editorial standards.

Shop
Tutors

If $f(x)=\frac{1}{\sqrt{x^{2}-1}}$, then f'(x) equals:

E

Editor

Sep 18, 2022

If $f(x)=\frac{1}{\sqrt{x^{2}-1}}$, then f'(x) equals:

Difficulty: Easy

A:

\frac{2}{\sqrt{x^{2}-1}}

B:

-\frac{x}{\sqrt{(x^{2}-1)^{3}}}

C:

\frac{x}{\sqrt{x^{2}-1}}

D:

\frac{3x}{\sqrt{x^{2}-1}}

ID: 63273db8ca83163ac3a102c3