If $\alpha, \beta\:and\:\gamma$ are the measures of angles of a triangle and a,b and c are the lengths of opposite these angles, then according to law of sine

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Sep 18, 2022

If $\alpha, \beta\:and\:\gamma$ are the measures of angles of a triangle and a,b and c are the lengths of opposite these angles, then according to law of sine

Difficulty: Easy

a^{2}=b^{2}+c^{2}-2bc\sin\alpha

a^{2}=b^{2}+c^{2}-2bc\cos\alpha

c^{2}=a^{2}+b^{2}-2ab\sin\alpha

$\frac{a}{\sin\alpha}=\frac{b}{\sin\alpha}=\frac{c}{\sin\alpha}

ID: 63273db9ca83163ac3a1099b