$\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=$

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$\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=$

E

Editor

Sep 18, 2022

\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=

Difficulty: Easy

A:

0

B:

1

C:

2

D:

-2

View Solution Steps

ID: 63273dbaca83163ac3a12357