$\coth^{-1}x$=

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$\coth^{-1}x$=

E

Editor

Sep 18, 2022

$\coth^{-1}x$=

Difficulty: Easy

A:

ln(x+\sqrt{x^{2}-1})

B:

ln(x+\sqrt{x^{2}+1})

C:

\frac{1}{2}ln(\frac{1+x}{1-x})

D:

\frac{1}{2}ln(\frac{x+1}{x-1})

ID: 63273db8ca83163ac3a105ff