$2+4+8+16+...+$ till $\frac{n}{2}$ terms=?

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$2+4+8+16+...+$ till $\frac{n}{2}$ terms=?

E

Editor

Sep 18, 2022

$2+4+8+16+...+$ till $\frac{n}{2}$ terms=?

Difficulty: Easy

A:

2^{n}

B:

2^{\frac{n+2}{2}}-2

C:

2^{\frac{n}{2}}+2

D:

None of these

View Solution Steps

ID: 63273dbaca83163ac3a12ca5